What to expect from this

[Sisi]

Hi. New to rabbits and curious.
I just got this doe and plan to breed her to a black male when she is old enough.
Her father is the same color as her.
The mother was a NZW/ Cali cross ( hvite with darker ears, nose)
Her littermates was several reds( like this), one black, two whites and one cali with black markings.
The buck I plan to use has black only breeding behind I think.

I also got her black sister. Will she only give black kits paired with a black male?

 

[tambayo]

Self i.e. solid black as the sister is will give self when bred to self. Code is aa and that hides behind A and at , so needs 2 (one from each parent) to show. If both carry a dilute (so Dd instead of DD) like blue you may end up with blue kits (or blue carriers).
Your other doe (on 3 pictures) is dilute, but how much i don't know enough for.
I am trying to complete the what color genes are in this rabbit puzzle for mine now that i have 3rd generation in the nestbox, but some letters are still blanc.
For guidance i used this page :
http://yellowbrookrabbitry.com/complete-rabbit-colour-genetics-guide/

 

[judymac]

Okay, she looks like a fawn agouti, doesn't appear to have the rufus modifiers to turn the color into red. Her father is the same color, mother is a pointed white (a.k.a. Californian, Himalayan). Siblings are black and a black pointed white. So, let's look at the possible genetics:

Agouti, coded 'A' is dominant. Fawn is agouti so we know there is one dominant 'A', pointed whites are generally non-agouti, so mom would have donated a recessive 'a', so the rabbit would be 'Aa'

Black/brown is coded 'B'. The siblings both carry black, typical Flemish Giant fawn is black-based, mom probably has black points, so the rabbit would be either 'BB' or "Bb'.

The dad is a full-color fawn, 'C', it's unknown if he has a more recessive allele with that; mom would be recessive 'c(h)' (the 'h' stands for Himalayan). Since there were white kits in the litter, both parents must carry recessive albino 'cc'. Since the rabbit in question is a full-color fawn, we know she has 'C' from her dad, mom could only have donated either her c(h) Cal pattern or the REW albino as the recessive allele (allele is just a fancy word for a possible choice on any given gene.) So, she'll either be 'C c(h)' or 'Cc'.

All of the rabbits shown are dense color, not diluted pastels, she's at least 'Dd', and probably 'DD'.

The last main gene is the extension gene, coded 'E'. Of the five possibilities on this gene, it looks like only two are in play here, normal extension 'E' like the black sibling, and the non-extension fawn recessive 'ee', where the black/brown coloration does not extend to the body. In fawn, the agouti banding is simply fawn with white undercolor, no colored bands. Since the rabbit is a fawn, she must be 'ee'.

When you don't know what the second allele is with a dominant gene, we just put a dash after the dominant gene. That gives us A-B-Cc(h) or Cc D- ee for the doe. If the potential mate was a black, it would be recessive non-agouti aa, BB or Bb for dominant black, full color C-, dense color D-, and normal extension E-.

What could the kits be? Dad can only give non-agouti, mom could give either agouti or not, depending on her recessive. If she carries Aa, there's a 50/50 chance the kits would be self-colored. If she's AA, all of the kits will be agouti based, no blacks. There's a good chance the kits will carry black, not chocolate, unless both parents have an unknown chocolate recessive. Black-based colors would include black tortoiseshell, black, chestnut/sandy, fawn, Californian, and some albino whites.

Black buck would be full-color C-, the doe is full color C-, so if he carries an albino recessive, here's the possibilities. A Punnet square shows the possible combinations, in this case there's a 1 in 4 chance of a REW kit. (Sorry, mistyped albino in chart)

If the doe ended up with mom's Cal pattern, and the buck still has a recessive white:

In this case, there's a 1 in 4 chance of Cal pointed white kits.
However, if the buck has only two dominant full-color genes, he can only donate a dominant gene, and every kit will be full-color, no Cals or albino kits.

As far as the fawn recessive goes, we know your doe can only donate a recessive fawn allele. If the buck has two dominant normal extension alleles, none of the kits will be fawn, although they will all carry a fawn recessive. If they also get non-agouti 'aa', they could be blacks.

If the buck carries a recessive fawn allele, the kits will be:

That's a 50/50 chance of fawn kits.

That's a long answer to a simple question, but there's a lot of recessive possibilities.

 

[Sisi]

Wow, thank you so much for that long answer

 

[judymac]

You also asked about the black sister. Non-agouti aa, black B-, color C-, dense D-, normal extension E. Crossed with a black buck, all the kits would be non-agouti, probably black-based although the chance for recessive chocolate always exists. Full-color x full-color gives a 3 out of 4 chance for full-color kits, even if they both carry a recessive for albino or Californian. Same thing with dense x dense, there's a 3 out of 4 chance for normal dark black color, even if both carry a recessive for dilute. Same with fawn, if both are normal extension, there's a 3 out of 4 chance the kits will be normal extension, even if they both have a recessive for fawn.

 

[judymac]

Should have explained the Punnet squares in the earlier post, sorry about that. Each rabbits inherits one copy of each gene from each parent. So, for every gene, a kit is born with two possibilities, called 'alleles'. Some genes only have two choices, like the 'B' black gene. If they inherit a dominant black 'B', they'll show the black traits, even if they get a recessive brown from the other parent. It will take both alleles being brown for brown to be expressed.

The purpose of the Punnet square is to show the possible combinations of those alleles. For instance, if you have a black buck with a chocolate recessive, Lady Luck could choose either the black or the chocolate gene as his contribution to one of the kits. Same with the doe. So, the Punnet square shows what alleles the buck and doe has for a given gene, one writtenacross the top of the chart and the other down the side. It really doesn't matter which order they go in, the buck can be either down the side or across the top, it will work just the same. For this example, we'll put the buck across the top.

To read the square, just pick one of the alleles on the top, and follow it down to the first box down the column. Look across the row, and see what allele the doe could contribute in that row. The letters in the box will contain the buck's allele from that first column, and the doe's allele from the first row.

When you've completed all four boxes, you'll see every possible combination from that mating. In this case, BB and Bb will both be black, bb is chocolate. So even with both parents having a chocolate recessive, only one kit out of four has a chance of being chocolate. Again, that's just on average. Lady Luck can cause wild swings in any given litter, you could have all chocolate or none, we're just talking odds. The square is just a way to visualize the possibilities for each gene. You could do multiple genes in one square, but it quickly gets very unwieldy. A square for just two traits at once has 16 boxes.