Mini Lop Mama
Mini Plush Lops Furever
- Joined
- Apr 10, 2022
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That doe came straight from the original lines for Mini Plush Lops. She only had two generation as the pedigree got lost.Where's the rest of the pedigree?
Thank you, thank you, thank you for your time and this fantastic answer!!D: Dense color is dominant; dilute (weaker, pastel) color is recessive. Your buck is full dense color if he is an orange, but he has an opal ancestor, which is a recessive dilute. The doe is also a dilute. Let's guess he still carries the dilute recessive, and is Dd, she would be recessive dd.
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So, there's a 50/50 chance of full color (like chestnut agouti, black, chocolate) and a 50/50 chance of dilute color (opal, blue, lilac). If the buck is really all full color DD, all the kits will be full dense color, but will carry dilute.
E: Steel is dominant E(S), then in descending order of dominance: normal extension of color E, then harlequin e(j), and lastly recessive fawn ee (also called orange, as well as the dilute version called fawn or cream depending on breed, and the rufus modified red/copper). There's actually a very rare dominant black agouti E(D) that is agouti but turns everything black that is dominant over everything, but you're not likely to run into it.) Your orange buck will be the most recessive ee, so he can only contribute an 'e'. Marten is normal extension E. Assuming there's no steel or harlequin hiding in the background, and assuming there is no recessive fawn in the doe's pedigree (which is hard to tell, because both sable and chin don't allow any any existing fawn genetics to actually produce that color in the hair), we get. . .
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Which means that there will be no orange kits, but they will all carry the recessive genetics for it when bred back to an orange, where you have 50/50 odds of getting oranges in the next generation. Of course, if the doe actually has a recessive orange gene hiding in there, then your odds go up to 50/50 in her litter to the orange buck.
En spotting is dominant, not-spotted is recessive. Your doe is out of a broken chinchilla, but she is listed as a Vienna carrier VC, not Vienna marked VM. If she did have white markings, it might be difficult to deduce whether it was due to the Vienna blue-eyed white gene, or to the broken En spotting, or both, as 'booted' brokens with little white markings can look just like the Vienna Dutch-marked VM rabbits due to the Vienna gene. Since she is not marked, she is not a broken carrier. Broken is dominant, so a recessive is simply not spotted, and can't carry the dominant broken genetics. Neither the buck or doe seems to be broken, so they can only pass along the recessive non-broken genetics.
Vienna blue-eyed white is recessive, non-Vienna normal is dominant. Which finally brings us to the last letter in this alphabet soup. Vienna genetics are insidious, often cropping up generations later. Your buck doesn't show any Vienna, but the doe MAY be a carrier, as her mother was a white-eared, Vienna marked rabbit, and I don't know what goes behind that. If the doe is not a carrier, then she shouldn't pass along any of the Vienna traits. If she is a carrier, even though she doesn't exhibit any blue-eyed white traits, here's what you can expect. . .
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This means even though neither parent has any outward signs of the Vienna blue-eyed white gene, half of the kits will still be Vienna carriers, or Vienna marked (usually a white snip on the nose, white on the feet, sometimes white on the chest or where a Dutch rabbit would have white markings, which is why it is sometimes called Dutch-marked.) If you mate two of these VM/VC rabbits together, you have a 1 in 4 chance of getting Vienna blue-eyed white kits. Of course, you can't tell which kit is a Vienna carrier, and which is not Vienna by looking at them, which is how this genetics can keep showing up long after the initial Vienna carriers are off the pedigree. When they have the Vienna marks, that makes it easy to tell.
So, what does all this mean? These odds are the odds for any one given kit to be a certain color. Enter Lady Luck, and the whole probability things goes askew. You could get all bucks, or all does, even though the expected odds are closer to 50/50. Same with any of these colors. We're just playing the odds here.
A: 50% chance of agouti, 25% tan, 25% self non-agouti
B: Probably black-based colors (black or blue with dilution)
C: 50% chance of full color, 25% chance of chinchilla, 25% sable
D: 50/50 chance full dense color vs. dilute.
E: Not expecting orange, but the kits will all carry the recessive; unless the doe has recessive fawn hiding in the background, which would up the odds to 50/50.
En: No spots expected
V: No blue-eyed white kits, but half of the kits should be carriers of the BEW genetics, and may have white spots show up on toenails, feet or face that render the kits unshowable.
How does this put together? Agouti + black = chestnut agouti, add in dilute and you get opal.
Tan + black = black otter, add in dilute and you get blue otter. Add in chin or sable and you get black or blue marten. Agouti + chinchilla + black = black chin, add in dilute and you get squirrel. Non-agouti + black + sable = Siamese sable, add in dilute and you get a blue smoked sable. If you get any chocolate based or orange based colors (like torts or oranges), you know both parents have to carry that trait. Long answer to a short question.
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