I was wondering is it possible for a Harlequin and Sable point to produce magpies? I was under the impression it wasn't? These are the two her and my black orange Harlequin produced.
Yes. A magpie is a harlequin in which the orange color is suppressed, leaving white where the orange would have been. Both chinchilla <
c(chd)> and sable <
c(chl)> restrict the production of pheomelanin (the yellow pigment that makes orange/red tones). The main difference between a chin-based magpie and a sable-based magpie is that in addition to suppressing the yellow pigment, the sable allele also affects the dark pigment, causing black to be somewhat less black. It's often more of a sepia tone, but the range of color is wide and it can be very dark, especially if there are two sable alleles (<
c(chl)c(chl)> called seal, which is pretty well described as "almost black").
There are actually at least three ways you could get magpies out of a sable x harlequin cross, which would depend on what the parents carried in the second place at their C loci.
The C locus has the following known alleles, in order of descending dominance. Even though there is some co-doinance, generally a more dominant alelle will cover up/hide the affects of a more recessive allele.
C – full-color: all pigments allowed to show (DOMINANT, WILD TYPE)
c(chd) – chinchilla: suppresses most/all pheomelanin production in fur
c(chl) – sable/shaded: suppresses all pheomelanin, interferes with eumelanin so that black appears sepia and eyes have a ruby glow; short hair less affected so rabbit is “shaded”
c(h) – himalayan: suppresses all pheomelanin production, and is temperature-sensitive so eumelanin is generally produced only on extremities; prevents all pigmentation in eyes
c – REW: all pigment production is suppressed in skin, fur and eyes. A REW rabbit still has all other color and pattern genes, but they cannot be expressed if the individual has two copies of this allele
A full-color harlequin is <
C_>, where the capital C means full color and the understrike means you don't know what's there - it could be another C, or any of the others.
A sable is <
c(chl)_>, with the understrike being either himalayan <
c(h)> or REW <
c>. It can't hide a
C or
c(chd) because they're more dominant, and if the second allele was another sable allele, the rabbit would look like a seal ("almost black") rather than a sable.
SO... If the harlequin carried a chinchilla <
c(chd)>, that could pair up with the sable's <
c(chl)>, and you could get a harlequin with <
c(chd)c(chl)>. The chinchilla would suppress orange, and you'd get a chinchilla-based magpie.
If the harlequin carried a sable <
c(chl)>, that could pair up with the sable's <
c(chl)> to make a seal magpie, or it could pair with the sable's <
c(h)> or <
c> and make a sable magpie; in both cases the orange pigment is suppressed, leaving white in its place.
If the harlequin carried a <
c(h)> or <
c>, one of those could pair up with the sable's <
c(chl)>, which would dominate and produce a sable magpie <
c(chl)c(h)> or <
c(chl)c>.
Because your doe is a sable point, you know that she has two non-extension alleles <
ee>, which is the most recessive on the E locus. This means that the buck's harlequin allele <
e(j)> which is on the same E locus, will always pair with a non-extension <
e>, making <
e(j)e> which produces the harlequin pattern.