A pedigree is just a record of parentage - it doesn't record what any siblings might have been. Your rabbit won't (and can't!) carry all of those colours, and he may well carry some not seen on there.I just looked at his pedigree, he Carry’s, Chin, Self Chin, Rew, Dalmatian, magpie, red, harlequin, tri, cal, Amber, black, castor, fawn, and Otter. I have the 7 gen pedigrees for all my rabbits and that’s what I can see. As far as I know sable is something that NONE of my rabbits carry, cuz it’s not on any of they’re pedigrees.
californian is pointed, so there come the shaded genes.Californian.
You guys remind me of my recent HOUR LONG conversation explaining how a woman's AKC registered litter couldn't be the product of their alleged pedigree, despite the "but they're AKC registered" statement. It was a failed effort. Two solid black shepherds cannot ever have a Sable litter. Sable is never a recessive in German Shepherds, it always expresses.He's agouti based, as he has ticking, white ear lacing and nostrils (and certainly will have a white belly as well)... so he's A_. His base colouring is black, so B_.
He has shading so he's not a chinchilla; he has black eyes so he's not Cali or Himi, and he's not a REW so he must be c(chl). He seems light on body colour so he might carry REW or Himi, meaning he's c(chl)c or c(chl)c(ch).
He's not a dilute colour such as blue or lilac, so D_.
The remaining part of the equation is his e locus - He's not harlequin or magpie, and he's not steel so that eliminates e(j) and E(s) meaning he could be E_ but non-extension could also be possible, that would make him ee which is a sable Frosty. If he was chin +ee he would be an ermine and he has way too much ticking for that.
Is dominant black, KB, in the breed? It could be possible if one parent was dominant black and the other recessive black.You guys remind me of my recent HOUR LONG conversation explaining how a woman's AKC registered litter couldn't be the product of their alleged pedigree, despite the "but they're AKC registered" statement. It was a failed effort. Two solid black shepherds cannot ever have a Sable litter. Sable is never a recessive in German Shepherds, it always expresses.
I've learned the hard way to "never say never" in genetics, haha...there are too many unknowns, modifiers, unexpected interactions and linkages, etc. For example, I used to say that if you bred two (recessive) rex-coated rabbits, you'd always get rex-coated kits. Until I discovered that there is not one, not two, but at least three different genes that produce that coat type (that we know of so far)! And they don't always cooperate with each other to make a rex coat... so you *can* get a normal-furred rabbit out of two rex-coated ones!You guys remind me of my recent HOUR LONG conversation explaining how a woman's AKC registered litter couldn't be the product of their alleged pedigree, despite the "but they're AKC registered" statement. It was a failed effort. Two solid black shepherds cannot ever have a Sable litter. Sable is never a recessive in German Shepherds, it always expresses.
I can't even begin to unravel the rabbit coloration, so I think I'll stick with something simple: Champagne D'Argent is what I'm looking at getting.
There isn't a dominate black gene in German Shepherds, it's a recessive (bb) requiring two to express. Sable IS dominate, requiring only one to express. White is a masking gene & is the only thing that can cover a Sable (although we have a dilute allele but that's another matter).Is dominant black, KB, in the breed? It could be possible if one parent was dominant black and the other recessive black.
Sorry, it was my fault. Genetics of color is something I've always been interested in.Wait how did this go from rabbits to dogs
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